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Bug #65533
closedqa/vstart_runner.py: don't let command run after timeout
% Done:
0%
Source:
Tags:
Backport:
Regression:
No
Severity:
3 - minor
Reviewed:
Description
LocalRemote.run() accepts parameter timeout
but it is not passed to subprocess
and therefore has no effect.
Updated by Rishabh Dave 12 days ago
- Status changed from Fix Under Review to Resolved
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